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==== Calculate Tension Force in the Stay: ==== | ==== Calculate Tension Force in the Stay: ==== | ||
Calculate the resultant load due to the self weight of the jib: <math>3.5\times50 = 175kN</math> at 25m. | |||
==== Take moments about A: ==== | |||
<math>\sum{M}= (100\times45)+(175\times25)-(F_{y}\times30)=0</math> | |||
<math>F_y=296kN</math> | |||
==== Resolve forces to find the total cable force: ==== | |||
<math>\theta = \tan^{-1}(\frac{20}{30}) = 34^\circ </math> | |||
<math>F_{t}=\frac{F_y}{\sin\theta}=\frac{296}{\sin45^\circ}=529</math> | |||
[[File:Crane-stay-sch-fbd.png|none|thumb|Free Body Diagram of the Jib]] | |||
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